# Absolute Arithmetic and F1-geometry by Koen Thas

By Koen Thas

It's been identified for a while that geometries over finite fields, their automorphism teams and sure counting formulae concerning those geometries have fascinating guises while one shall we the scale of the sector visit 1. nevertheless, the nonexistent box with one aspect, F1

, provides itself as a ghost candidate for an absolute foundation in Algebraic Geometry to accomplish the Deninger–Manin application, which goals at fixing the classical Riemann Hypothesis.

This booklet, that's the 1st of its variety within the F1

-world, covers a number of parts in F1

-theory, and is split into 4 major components – Combinatorial conception, Homological Algebra, Algebraic Geometry and Absolute Arithmetic.

Topics handled comprise the combinatorial idea and geometry at the back of F1

, express foundations, the combination of other scheme theories over F1

which are almost immediately on hand, explanations and zeta features, the Habiro topology, Witt vectors and overall positivity, moduli operads, and on the finish, even a few arithmetic.

Each bankruptcy is thoroughly written by means of specialists, and in addition to elaborating on identified effects, fresh effects, open difficulties and conjectures also are met alongside the way.

The variety of the contents, including the secret surrounding the sector with one point, may still allure any mathematician, despite speciality.

Keywords: the sphere with one aspect, F1

-geometry, combinatorial F1-geometry, non-additive classification, Deitmar scheme, graph, monoid, intent, zeta functionality, automorphism crew, blueprint, Euler attribute, K-theory, Grassmannian, Witt ring, noncommutative geometry, Witt vector, overall positivity, moduli house of curves, operad, torificiation, Absolute mathematics, counting functionality, Weil conjectures, Riemann speculation

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**Additional info for Absolute Arithmetic and F1-geometry**

**Example text**

If f (z) = 0 then, as z is an atom, it follows that α(c) = z. If f (z) = 0, then z has a preimage y ∈ |Y |. This comes from some b ∈ |B|, which maps to a preimage of z in C. All these elements, including b, may be chosen to be admissible, so the claim follows. The proof of (b) is similar. 5. Ascent functors. 1. A functor between pointed categories is called pointed , if it maps a zero object to a zero object. A pointed functor between belian categories is called strong-exact if it maps strong-exact sequences to exact sequences.

We say that 41 Belian categories C contains enough injectives, if for every object X there exists a monomorphism X → I for some injective object I. An object is called projective, if it is injective in the opposite category C opp where all arrows are reversed. This means that P is projective if for every epimorphism ψ : A B the induced map Hom(P, A) → Hom(P, B) is surjective. We say that C has enough projectives, if C opp has enough injectives. This means that for every object X there exists an epimorphism P X, where P is projective.

Next, let 0 = x ∈ |ker(δ)| be an admissible atom. We have to show that there exists an admissible atom u in | ker(f2 )| such that α(u) = x. Pick an admissible pre-image 0 = z ∈ |Z| under s. We have to show that z can be chosen such that l(z) ∈ | ker(f2 )|. 8. By exactness, we have ker(k ) = im(f1 ) so that there exists an admissible atom w ∈ |X1 | with f2 (l(z)) = f2 (g1 (w)). By admissiblity, l(z) is an atom, and as f2 is strong, it follows that either f2 (l(z)) = 0, or l(z) = g1 (w). As the first case is what we want, we deal with the second now.